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4x^2-43x-37=0
a = 4; b = -43; c = -37;
Δ = b2-4ac
Δ = -432-4·4·(-37)
Δ = 2441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-43)-\sqrt{2441}}{2*4}=\frac{43-\sqrt{2441}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-43)+\sqrt{2441}}{2*4}=\frac{43+\sqrt{2441}}{8} $
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